MATHS OBJ:
1-10: CBBCCACBBC
11-20: CACBAAAADB
21-30: BBADBCCACB
31-40: BBCACBDADA
41-50: DDACCCDDCB
Expogod.comEXPOGOD.COMMATHS THEORY ANSWERS:
(1a)
(y-1)log4=ylog16
log4^(y-1)=log16^y
log4^(y-1)=log4^2*y
y-1=2y
y=-1
(1b)
Distance =speed*time
let the time of the walk be x hours
=>4*(x+0.5)=5x
Because 30 minutes 0.5hours
4x+2=5x
5x-4x=2
x=2hours
=>5*2
=10km
================================
(2a)
2/3(3x-5)-3/5(2x-3)=3
2/3(3x-5)-3/5(2x-3)=3
lcm=15
=>(6x-10)/3-(6x-9)/9=3
Multiply both sides by 15
15(6x-10)/3-15(6x-9)5=15(3)
30x-50-3(6x-9)=45
30x-50-18x+27=45
12x-23=45
12x=45+23
x=68/12
x=5(2/3)
(2b)
=180-n-88=92-n
Also UTQ=180cm--(sum of 80+92-n+180-m=180(sum of 352-n-m=180
-n-m=180-352
-n-m=-172
-(n+m)=-172
m+n=172degrees
=============================================
(3a)
DRAW THE DIAGRAM
tanx=50/x
tan66.4=50/x
x=50/2.289
x=21.844m
x=22m
(3b)
DRAW THE DIAGRAM
Area of =1/2*10*h=45
=>5h=45
h=45/5
h=9cm
Area of parallelogram=L*h
=9*6
=54cm^2
Therefore the area of QTUS=54+45
=99cm
================================================
(4a)
Tnth=a+(n-1)d
Snth=n/2[2a+(n-1)d]
T6th=37
S6th=147
T6th=>37=a+(6-1)d
=>37=a+5d-----(i)
S6th=>147=6/2[2a+96-1)d
=>147=3(2a+5d)
147=6a+15d------(ii)
Therefore a+5d=37----(i)
6a+15d=147-----(ii)
divide equation ii by 3
2a+5d=49--(ii)
multiply eq i by ii
=>a+10d=74
a+5d=49
5d/5=25/5
therefore d=5
substitute for d in eq i
a+5d=37
a+5(5)=37
a=37-25
a=12
The first term=12
(4b)
Sn=n/2[2a+(n-1)d]
S15=15/2[2(12)+(15-1)5]
=15/2(24+(14*5)
=7.5(24+70)
=705
========================================
expogod.com(5a)
Let bag =B
shoe=S
U=120
n(BnS)=45,
n(S)=x+11
n(B)=x
n(SnB^1)=x+11-45
=x-34
n(BnS^1)=x-45
(5b)
DRAW THE VENN DIAGRAM
x-45+45+x-34=120
2x-34=120
2x=120+34
2x/2=154/2
x=77
=11+x
=11+77=88
Therefore 88customers bought shoes
(5c)
Pr(bag)=n(B)/U=77/120
Expogod.comSECTION B:(8) Tabulate:X = 1,2,3,4,5F = m+2, m-1, 2m-3, m+5, 3m-4 = 8m - 1Fx = m+2, 2m-2, 6m-9, 4m+20, 15m-20 = 28m - 9But x̄ ( this symbol (x̄) means X bar) = 75/23ΣFx / Σf = 75/23 = 28m - 9/8m-175/23 = 28m - 9/8m - 1Cross multiply 75(8m-1) = 23(28m-9)600m - 75 = 644m - 207-75 + 207 = 644m - 600m132 = 44mM = 3(8b)In tabular formX = 1,2,3,4,5F = 5,2,3,8,5Cum Freq= 5,7,10,18,23Q1 = (N+1/4) = (23+1/4)= 6Q3 = (3N + 1/4) = (3*23+1/4)= 18Inter quarter range = Q3 - Q1= 18-6= 12(8bii)Pr. (at least 4 mark)= 8+3+2+5/23= 18/23(10) Sin x = 5/13Using pythagoras ruleM^2 = 13^2 - 5^2 (^ means Raise to power)M^2 = 169 - 25M ^2 = 144M = √144M = 12Hence: Cos x - 2sin x / 2tan x12/13 - 2(5/13) / 2(5/12)= 12/13 - 10/23 / 5/6FIND LCM= 12 - 10/13 / 5/6= 12/65(10b) Draw a triangle LACBin triangle LCBHyp^2 = Opp^2 + Adj^212^2 = 9.6^2 + |CB|^2144 = 92.16 = |CB|^2144 – 92.16 = |CB|^251.84 = |CB|^2therefore, |CB| = √51.84|CB| = 7.2m|AC| + |CB| =|AB||AC| + 7.2m = 10m|AC| = 10m – 7.2m|AC| = 2.8mIn triangle LCAHyp^2 = Opp^2 + Adj^2|LA|^2 = |AC|^2 + |LC|^2|LA|^2 = 2.8^2 + 9.6^2|LA|^2 = 7.84 + 92.16|LA|^2 =100|LA| = √100|LA| = 10m(10bii) in triangle LCAsinθ = Opp/Hypsinθ = |LC|/|LA|sinθ = 9.6/10sinθ = 0.96θ = sin^-1 (0.96)θ = 73.74==============================Expogod.com
SECTION B:(8) Tabulate:X = 1,2,3,4,5F = m+2, m-1, 2m-3, m+5, 3m-4 = 8m - 1Fx = m+2, 2m-2, 6m-9, 4m+20, 15m-20 = 28m - 9But x̄ ( this symbol (x̄) means X bar) = 75/23ΣFx / Σf = 75/23 = 28m - 9/8m-175/23 = 28m - 9/8m - 1Cross multiply 75(8m-1) = 23(28m-9)600m - 75 = 644m - 207-75 + 207 = 644m - 600m132 = 44mM = 3(8b)In tabular formX = 1,2,3,4,5F = 5,2,3,8,5Cum Freq= 5,7,10,18,23Q1 = (N+1/4) = (23+1/4)= 6Q3 = (3N + 1/4) = (3*23+1/4)= 18Inter quarter range = Q3 - Q1= 18-6= 12(8bii)Pr. (at least 4 mark)= 8+3+2+5/23= 18/23(10) Sin x = 5/13Using pythagoras ruleM^2 = 13^2 - 5^2 (^ means Raise to power)M^2 = 169 - 25M ^2 = 144M = √144M = 12Hence: Cos x - 2sin x / 2tan x12/13 - 2(5/13) / 2(5/12)= 12/13 - 10/23 / 5/6FIND LCM= 12 - 10/13 / 5/6= 12/65(10b) Draw a triangle LACBin triangle LCBHyp^2 = Opp^2 + Adj^212^2 = 9.6^2 + |CB|^2144 = 92.16 = |CB|^2144 – 92.16 = |CB|^251.84 = |CB|^2therefore, |CB| = √51.84|CB| = 7.2m|AC| + |CB| =|AB||AC| + 7.2m = 10m|AC| = 10m – 7.2m|AC| = 2.8mIn triangle LCAHyp^2 = Opp^2 + Adj^2|LA|^2 = |AC|^2 + |LC|^2|LA|^2 = 2.8^2 + 9.6^2|LA|^2 = 7.84 + 92.16|LA|^2 =100|LA| = √100|LA| = 10m(10bii) in triangle LCAsinθ = Opp/Hypsinθ = |LC|/|LA|sinθ = 9.6/10sinθ = 0.96θ = sin^-1 (0.96)θ = 73.74==============================Expogod.com(13ai)givenx(*)y=x+y/23(*)2/5=3+2/5/2=(15+2/5)*1/2=17/5*1/2=17/10= 1,7/10(13aii)8(*)y=8^1/4=8+y/2 =33/432+4y=664y=66-324y=34y=34/4y=17/2y=8^1/2(13b)given DABCAB=(^-4/6) and AC =(3/^-8)so AP =1/2(^-4/6)AP=(^-2/3)henceCP = CA + APCP= -(3/^8)+(^-2/3)CP = (^-5/11)(13ai)givenx(*)y=x+y/23(*)2/5=3+2/5/2=(15+2/5)*1/2=17/5*1/2=17/10= 1,7/10(13aii)8(*)y=8^1/4=8+y/2 =33/432+4y=664y=66-324y=34y=34/4y=17/2y=8^1/2(13b)given DABCAB=(^-4/6) and AC =(3/^-8)so AP =1/2(^-4/6)AP=(^-2/3)henceCP = CA + APCP= -(3/^8)+(^-2/3)CP = (^-5/11)========================
More Answers Loading....
========================
IMPORTANT UPDATE:
If subscribed or you are subscribing for Our Runs, pls remove ur phone from
DND to always receive our updates and answers!!!
To unsubscribe from Do Not Disturb (DND):
1. Text STOP to 2442
2. Then, text ALLOW to 2442
And send your mtn 500 to 09064911281. For you to receive the answers direct to your mobile phones immediately....
MATHEMATICS answers, has been posted already for OUR subscribers, But you can
Or You
Subscribe now with expogod.com and make your papers once.Subscription cost 3,000naira for all SUBJECTS (BOTH PRACTICAL )To subscribed call or whatsapp 09064911281